15m^2=-28m-12

Solution for 15m^2=-28m-12 equation:

15m^2=-28m-12

We move all terms to the left:

15m^2-(-28m-12)=0

We get rid of parentheses

15m^2+28m+12=0

a = 15; b = 28; c = +12;
Δ = b2-4ac
Δ = 282-4·15·12
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-8}{2*15}=\frac{-36}{30}
=-1+1/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+8}{2*15}=\frac{-20}{30}
=-2/3
$